+1 vote
in Physics by kratos

The pitch of a gauge is 0.5 mm and there are 50 divisions on circular scale. When there is nothing between the two ends (studs) of gauge, 45th division of circular scale is coinciding with **** gauge and in this situation, zero of main scale is not visible. When a wire is placed between the studs, the linear scale reads 2 divisions and 20th division of circular scale coincides with reference line. For this situation, mark the correct statement()

(a) Least count of the instrument is 0.01 mm

(b) Zero correction for the instrument is + 0.45 mm

(c) Thickness of wire is 1.65 mm

(d) All of the above

1 Answer

+4 votes
by kratos
 
Best answer

The correct option is (d) All of the above.

Explanation:

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