Find the equation() of the tangent() to the curve y = (x3 - 1)(x - 2) points where the curve intersects the x-axis.
When y = 0, we have (x - 1) (x2 + x + 1) (x - 2) = 0
i.e., x = 1 or 2.
The required equations of the tangents are y - 0 = -3(x - 1) or , y = -3x + 3 and y - 0 = 7(x - 2) or, y = 7x - 14.