$(+ "d"["SO"\_3("g")])/"dt" = (-"2d" ["O"\_2("g")])/"dt"$
Explanation:
For an elementary reaction,
[\ce{2SO2(g) + O2(g) -> 2SO3(g),}] the instantaneous rate of reaction is expressed as,
$"r"_"inst" = (-1)/2 "d" (["SO"\_2])/"dt" = - ("d"["O"\_2])/"dt" = 1/2 ("d"["SO"\_3])/"dt"$
Thus, $("d"["SO"\_3])/"dt" = (- "2d" ["O"\_2("g")])/"dt"$