$(-2)/3 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$
Explanation:
For elementary reaction,
[\ce{3H2_{(g)} + N2_{(g)} -> 2NH3_{(g)}}]
Rate of reaction = $(- 1)/3 ("d"["H"\_2])/"dt" = (- "d" "N"_(2("g")))/"dt"$
$= 1/2 ("NH"_(3("g")))/"dt"$
From the given 2nd options is correct.
$(-2)/3 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$