+1 vote
in General by kratos

For the elementary reaction, [\ce{3H2_{(g)} + N2_{(g)} -> 2NH3_{(g)}}] identify the correct relation among the following relations.

  • $(-3)/2 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$
  • $(-2)/3 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$
  • $("d"["NH"\_(3("g"))])/"dt" = (-1)/3 ("d"["H"\_(2("g"))])/"dt"$
  • $(-"d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$

1 Answer

+1 vote
by kratos
 
Best answer

$(-2)/3 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$

Explanation:

For elementary reaction,

[\ce{3H2_{(g)} + N2_{(g)} -> 2NH3_{(g)}}]

Rate of reaction = $(- 1)/3 ("d"["H"\_2])/"dt" = (- "d" "N"_(2("g")))/"dt"$

$= 1/2 ("NH"_(3("g")))/"dt"$

From the given 2nd options is correct.

$(-2)/3 ("d"["H"\_(2("g"))])/"dt" = ("d"["NH"\_(3 ("g"))])/"dt"$

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