25
Explanation:-
| Class | Frequency | Cumulative Frequency |
| 0 - 5 | 10 | 10 |
| 5 - 10 | 15 | 25 |
| 10 - 15 | 12 | 37 |
| 15 - 20 | 20 | 57 |
| 20 - 25 | 9 | 66 |
Now $N/2 = 66/2 = 33$ which **** in the interval 10 - 15. Therefore lower limit of the median class is 10.
The highest frequency is 20 which **** in the interval 15 - 20. Therefore, lower limit of modal class is 15.
Hence required sum is 10 + 15 = 25