+3 votes
in General by kratos

For the following equations, determine its order, degree (if exists)

$(("d"^3y)/("d"x^3))^(2/3) - 3 ("d"^2y)/("d"x^2) + 5("d"y)/("d"x) + 4$ = 0

1 Answer

+5 votes
by kratos
 
Best answer

Taking power 3 on both sides, we get

$(("d"^3y)/("d"x^3))^2 =( 3 ("d"^2y)/("d"x^2) - 5("d"y)/("d"x) - 4)^3$

In the equation (1)

The highest order derivative is $("d"^3y)/("d"x3$ and its power is 2.

Its order = 3 and degree = 2

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