+1 vote
in JEE by kratos

At ordinary temperature, the molecules of an ideal gas have only translational and rotational kinetic energies. At high temperatures they may also have vibrational energy. As a result of this at higher temperatures (Cv= molar heat capacity at constant volume) :–

(a) Cv = 3R/2 for a monoatomic gas

(b) Cv > 3R/2 for a monoatomic gas

(c) Cv > 5R/2 for a diatomic gas

(d) Cv = 5R/2 for a diatomic gas

1 Answer

+5 votes
by kratos
 
Best answer

Correct option**(c) Cv > 5R/2 for a diatomic gas**

Explanation:

Monoatomic gas Cv = 3R/2

This value is same for high temperature also, In case of diatomic gas

Cv = 5R/2 (at low temperature)

Also,Cv > 5R/2 (at high temperature due to vibrational kinetic energy)

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