Question

Near the point A (Fig. 3.10) lying on the boundary between glass and vacuum the electric field strength in vacuum is equal to E0 = 10.0 V/m, the angle between the vector E0 and the normal n of the boundary line being equal to α0 = 30°. Find the field strength E in glass near the point A, the angle α between the vector E and n, as well as the surface density of the bound charges at the point A.

Answer 1

Let the field in the dielectric be making an angle α with vector n. Then we have the boundary conditions,