Prove that the point (3, 0), (6,4) and (-1, 3) are the vertices of a right angled isosceles triangle.
Let A(3, 0), B (6, 4) and C(-1, 3) be the given points
⇒ AC=√ (16+9)
⇒ AC=√(25)
⇒ AB2=(√25)2
⇒ AB2=25
⇒ AC2=25
⇒ BC2=(√50)2
⇒ BC2=50
Since AB2+AC2=BC2 and AB=AC
∴ ABC is a right angled isosceles triangle