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Prove that: -1 + sin A sin ( 90° - A)/ cot ( 90° - A) = - sin^2 A
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asked
Jan 31, 2019
in
Class 11
by
kratos
Prove that:
-1 + sin A sin ( 90° - A)/ cot ( 90° - A) = - sin2 A
cbse
trigonometry
class-11
trigonometric ratios of acute angles
class-9
class-10
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answered
Oct 14, 2020
by
kratos
Best answer
-1 + sin A sin ( 90° - A)/ cot ( 90° - A) = - sin2 A
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