Find the area of the quadrilateral ABCD, the co-ordinates of whose vertices are A(5, - 2), B(- 3, - 1), C(2,7) and D(6,0).
Area of quadrilateral ABCD = ar (ΔABC) + ar (ΔADC)
ar (quad. ABCD) = 1/2 [5 (– 1) – (– 2) (– 3) + (– 3) (1) – (– 1) (2) + (2 × 0 – 1 × 6) + 6 (– 2) – (0 × 5)]
= 1/2 [– 30]
= |– 15|
= 15 sq. units
