+2 votes
in Physics by kratos

The effective cross section of a gold nucleus corresponding to the scattering of monoenergetic alpha particles within the angular interval from 90° to 180° is equal to Δσ= 0.50 kb. Find:

(a) the energy of alpha particles;

(b) the differential cross section of scattering d*σ/d*Ω (kb/sr) corresponding to the angle θ= 60°.

1 Answer

+5 votes
by kratos
 
Best answer

(a) According to the formula

(b) The differential scattering cross section is

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