+1 vote
in Class 12 by kratos

1 Answer

+1 vote
by kratos
 
Best answer

If m be mass of the satellite revolving round the earth of mass M along a circular orbit of radius r ,then gravitational pull on the satellite will provide the centripetal force required for circular motion. So we get

mw^2r=GmM /r^2, where w is the angular velocity of the satellite.

So w^2=GM/r^3

=> (4π^2)/T^2=GM/r^3, where T is the ** of circular mottion

This means T^2 is proportional to r^3

Hence

TA^2/TB^2=r1^3/r2^3

=>TA^2/TB^2=(4^3 r2^3)/r2^3

=>TA/TB=√64=8

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