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in JEE by kratos

In Lloyd' mirror experiment (Fig. 5.13) a light wave emitted directly by the source (narrow slit) interferes with the wave reflected from a mirror M. As a result, an interference fringe pattern is formed on the screen Sc. The source and the mirror are separated by a distance l = 100 cm. At a certain position of the source the fringe width on the screen was equal to Δx= 0.25 mm, and after the source was moved away from the mirror plane by Δh = 0.60 mm, the fringe width decreased η = 1.5 times. Find the wavelength of light.

1 Answer

+1 vote
by kratos
 
Best answer

From the general formula

Since d increases to d + 2 Δh when the source is moved away from the mirror plane by Δh.

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