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A photon with energy hω = 250 keV is scattered at an angle θ = 120° by a stationary free electron. Find the energy of the scattered photon.

+2 votes
in JEE by kratos

A photon with energy hω = 250 keV is scattered at an angle θ = 120° by a stationary free electron. Find the energy of the scattered photon.

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+3 votes
by kratos
 
Best answer

The wave length of the incident photon is

Then the wavelength of the final photon is

and the energy of the final photon is

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