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in Physics by kratos

In a chain of identical atoms the vibration frequency ω depends on wave number k as ω= ωmax sin (ka/2), where ωmax is the maximum vibration frequency, k = 2π/λ, is the wave number corresponding to frequency ω, a is the distance between neighbouring atoms. Making use of this dispersion relation, find the dependence of the number of longitudinal vibrations per unit frequency interval on ω, i.e. dN/dω, if the length of the chain is l. Having obtained dN/dω, find the total number N of possible longitudinal vibrations of the chain.

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+2 votes
by kratos
 
Best answer

If the chain has N atoms, we can assume atom number 0 and N +1 held ficed**. Then the displacement of the nth atom has the form**

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