+1 vote
in Mathematics by kratos

Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separatelv by 20 N force Mass per unit length of both the strings is same and equal to 1 g/m. When both the strings vibrate simultaneously the number of beats is

(a) 7

(b) 8

(c) 3

(d) 5

1 Answer

+2 votes
by kratos
 
Best answer

Correct option (a) 7

Explanation:

l1 = 0.516 m,l2=0.491 m, T =20 N

Mass per unit length, μ = 0.001 kg/m.

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