+2 votes
in JEE by kratos

Maximum intensity in YDSE is I0, Find the intensity at a point on the screen where

(a) the phase difference between the two interfering beams is pi/3

(b) the path difference between them is λ/4

1 Answer

+4 votes
by kratos
 
Best answer

(a) we have

Here Imax is I0 (i.e., intensity due to independent sources is I0/4). Therefore, at

(b) Phase difference corresponding to the given path difference Δx = λ/4 is

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