The correct thermodynamic conditions for the spontaneous reaction at all temperatures is
(a) ΔH < 0 and ΔS > 0
(b) ΔH < 0 and ΔS < 0
(c) ΔH < 0 and ΔS < 0
(d) ΔH > 0 and ΔS < 0
The correct option is : (a) ΔH < 0 and ΔS > 0
Explanation:
ΔG = ΔH - TΔS
If ΔH < 0 and ΔS > 0
then at all temperatures, ΔG = -ve, spontaneous reaction.
If ΔH < 0 and ΔS = 0
ΔG = (-ve) - T(0) = -ve at all temperatures.