Question

If a compound, on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is

(a) C2H2OCl

(b) CH2ClO

(c) CHCIO

(d) ClCH2O

Answer 1

Correct option (c) CHCIO

Explanation:

Therefore, empirical formula of the compound is CHClO.