Question

12 are distributed among three boxes. The probability that the first box contains 3 , is

(a) 110/9(2/3)10

(b) 9/110(2/3)10

(c) 12C3/312

(d) 12C3/123 29

Answer 1

Correct option is (a) 110/9(2/3)10

Explanation:

Since each ball can be placed in any one of the 3 boxes.

Thus, there are 3 ways in which a ball can be placed in any one of 3 boxes.

Thus, there are 312 ways in which 12 ***** can be placed in 3 boxes.

Required probability = 12C3/ 312 29

= 110/9 (2/3)10