If the function f (x) = ax^3 + bx^2 + 11x - 6 satisfies the condition of Rolle'* theorem in [1, 3] and f'(2 + 1/√3) = 0

Question 1

If the function f (x) = ax3 + bx2 + 11x - 6 satisfies the condition of Rolle'* theorem in [1, 3] and f'(2 + 1/√3) = 0, then the values of a and b are respectively.

(a) -1 and 6

(b) -2 and 1

(c) 1 and -6

(d) -1 and 1/2

Question 2

Correct Option (c) 1 and -6

Explanation:

If the function f (x) = ax^3 + bx^2 + 11x - 6 satisfies the condition of Rolle'* theorem in [1, 3] and f'(2 + 1/√3) = 0

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1 Answer

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If the function f (x) = ax^3 + bx^2 + 11x - 6 satisfies the condition of Rolle'* theorem in [1, 3] and f'(2 + 1/√3) = 0

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1 Answer

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