+2 votes
in JEE by kratos

A simple harmonic oscillation is represented by the equation y = 0.40 sin (440 t + 0.61) here, y and t are in m and * respectively. What are the values of

(i) amplitude

(ii) angular frequency

(iii) frequency of oscillations

(iv) time ** of oscillations and

(v) initial phase ?

1 Answer

+1 vote
by kratos
 
Best answer

The given equation is y = 0.40 sin (440 t + 0.61)

Comparing it with the equation of SHM y = a sin (ωt+ϕ0)

We have, (i) Amplitude, a = 0.40 m

(ii) Angular frequency, ω = 440 Hz

(iii) Frequency of oscillations,

(iv) Time ** of oscillations,

(v) Initial phase angle, ϕ0 = 0.61 rad.

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