The equation of the parabola with its vertex at the origin, axis on the y-axis and passing through the point (6, –3) is
(a) y2 = 12 x + 6
(b) x2 = 12y
(c) x2 = -12y
(d) y2 = -12 x + 6
Correct option (c) x2 = -12y
Explanation:
Since the axis of parabola is y-axis
∴ Equation of parabola x2 = 4ay
Since it passes through (6, – 3)
∴ 36 = -12a ⇒a = -3
∴ Equation of parabola is x2 = -12y.
