Given:
ABCD is a parallelogram. AC is one of the diagonals of the parallelogram ABCD.
To prove:
ar(ΔABC)=ar(ΔDBC)
Proof:
In triangles ABD and DBC,
AB = DC ( Opposite sides of parallelogram)
AD = BC ( Opposite sides of parallelogram)
BD = BD ( common side)
(area congruency axiom)
