Question

the sum of three consecutive terms in an AP is 6 & their product is -120 find the three terms

Answer 1

Let the consecutive terms in AP be

a-d, a and. a+d

So by 1st condition

a-d+a+a+d=6

=>a=2

By 2nd condition

(a--d)×a×(a+d)=-120

=>2(4-d^2)=-120

=>d^2=64

=>d=+8or-8

So three terms are

-6,2,10

Or 10,2,-6