The maximum value of [x(x-1)+1]1/3,0≤ x≤ 1 is
(A) (1/3)1/3 (B) 1/2
(C) 1 (D) 0
Then, we evaluate the value of f at critical point X= 1/2 and at the end points of the interval [0, 1] {i.e., at x = 0 and x = 1}.
Hence, we can conclude that the maximum value of f in the interval [0, 1] is 1. The correct answer is C.