Let the mass per unit area = m
M = mass of disc = πR2m = π(6)2m = 36πm
M1 = mass of removed disc = π(2)2m = 4πm
M2 = mass of remaining portion = M – M1 = 36πm – 4πm = 32πm
CM of disc is at origin
CM of removed disc = r1 = 3.2 cm.... (given)
CM of remaining disc = r2xad
hence