+3 votes
in Class 10 by kratos

Intercepts made on the axes by the circle whose equation is ax2 + ay2 + 2gx + 2fy + c = 0.

1 Answer

+3 votes
by kratos
 
Best answer

ax2 + ay2 + 2gx + 2fy + c = 0....(1)

The abscissa of the points where the circle (1) meets the axis of x i.e. y = 0, are given by the equation

ax2 + 2gx + c = 0 .......(2)

The roots of this equation being x1 and x2 we have

Again, the roots of the equation (2) are both imaginary if g2 < ac. In this case the circle does not meet the axis of x in real points, i.e. geometrically it does not meet the axis of x at all.

The circle will touch the axis of x if the intercept A1A2, be just zero, i.e. ii g2 = ac.

It will meet the axis of x in two points lying on opposite sides of the origin if the two roots of the equation (2) are of opposite signs, i.e. if c be negative.

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