Calculate the temperature of a furnace, when a 400g of copper ball, taken out from it, melts only 400g of ice to form water at 0°C. Take .H.C. of copper = 0.4Jg-1°C-1 and .L.H. of ice = 336Jg-1
Let temp. of furnace i.e. of copper ball = T°C
∴ Heat lost by copper ball = Heat gained by ice to melt to 0°C water
