Question

In the given figure, BAD = 60° ABD = 70°, BDC = 45°

(i) prove that AC is a diameter of the circle.

(ii) Find ACB

Answer 1

AC is the diameter of the circle.

[angle in a semi circle is 90°] proved

(ii) ACB = ADB = 45°

[ Angles in the same segment of a circle]