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in JEE by kratos

Calculate the molality of 1 L solution of 93 % H2SO4. (weight/volume).The density of the solution is 1.84 g/mL.

1 Answer

+4 votes
by kratos
 
Best answer

Given, 93% H2SO4 solution (weight/volume).

It means 93 g of H2SO4 present in 100 mL of solution, therefore,

weight of H2SO4 = 93 g

Volume of solution = 100 mL

.'. Weight of solution = 100 x 1.84 = 184 g

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