Fe^3+ + SNC^-(excess) → A(blood red) + F^-(excess) → B (colourless) Identify A and B.

Question 1

Fe3+ + SNC-(excess) → A(blood red) + F-(excess) → B (colourless)

Identify A and B.

(a) Write IUPAC name of A and B.

(b) Find out spin only magnetic moment of B.

Question 2

The IUPAC name of

A = Pentaaquathiocyanatoferrate (III) ion and

B = Hexafluoroferrate (III)

In [FeF6]3-, the coordination number of iron (Fe) is six and its oxidation number is +3.

kratos · Answer 1 · 2020-02-06T07:47:04+0000

The IUPAC name of

A = Pentaaquathiocyanatoferrate (III) ion and

B = Hexafluoroferrate (III)

In [FeF6]3-, the coordination number of iron (Fe) is six and its oxidation number is +3.

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