Given, Mass of the brick = 2.5 kg
Dimensions of the brick = 20 cm × 10 cm × 5 cm
So, Weight of the brick (Thrust/Force)
= F = mg = 2.5 × 9.8 = 24.5 N
(i) When the surface area 10 cm × 5 cm is in contact with the ground, then
(ii) When the surface area 20 cm × 5 cm is in contact with the ground, then
(iii) When the surface area 20 cm × 10 cm is in contact with the ground, then