+1 vote
in Class 11 by kratos

A circular loop of conducting wire of radius 1 cm is cut at a point A on its circumference. It is then folded along a diameter through A such that the two semicircular loops lie in two mutually perpendicular planes. In this region a uniform magnetic field B of magnitude 100 mT is directed perpendicular to the diameter through A and makes angles of 30° and 60° with the planes of the two semicircles. The magnetic field reduces at a uniform rate from 100 mT to zero in a time interval of 4.28 ms. Therefore

(a) instantaneous emf in the two loops are in the ratio √2 :1

(b) instantaneous emf in the two loops are in the ratio √3 :1

(c) the total emf between free ends at point A is 5 mV.

(d) the total emf between free ends at point A is 1.4 mV

1 Answer

+6 votes
by kratos
 
Best answer

Correct option (b, c)

Explanation:

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