Determine the osmotic pressure of a solution prepared by dissolving 2.5 mg of K2SO4 in 2L of water at 25C, assuming that it is completely dissociated.
ᴨ=i w R T/M V
i of K2SO4=3
w=.025g
R =.0821 L atm/K/mole
T=298K
M of K2SO4=174
V=2L
ᴨ =3 x.025 x.0821 x 298/174 x 2
=.00527Atm.
