+2 votes
in JEE by kratos

Find the value of 2 sin 3θ cos θ – sin 4θ – sin 2θ

1 Answer

+6 votes
by kratos
 
Best answer

= 2 sin 3θ cos θ – sin 4θ – sin 2θ

= 2 sin 3θ cos θ – [2 sin 3θ cos θ ] = 0

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