Find the position of the point (5, – 4) relative to the hyperbola 9x2 – y2 = 1.
Since 9(5)2 – (–4)2 = 1 = 225 – 16 – 1 = 208 > 0,
So the point (5,–4) inside the hyperbola 9x2 – y2 = 1.