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Ka for CH3COOH at 25C is 1.754 × 10^–5 . At 50C, Ka is 1.633 × 10^–5 What will be value of Δ * for the

+2 votes
in JEE by kratos

Ka for CH3COOH at 25C is 1.754 × 10–5 . At 50C, Ka is 1.633 × 10–5 What will be value of Δ * for the ionisation of CH3COOH ?

(A) –94.44 J/mole K

(B) –96.66 J/mole K

(C) –96.44 J/mole K

(D) –90.44 J/mole K

1 Answer

+6 votes
by kratos
 
Best answer

Correct option (C) –96.44 J/mole K

Explanation:

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