The correct option (a) 4m = 5n
Explanation:
x = acos3θ sin2θ
y = asin3θ cos2θ
∴ x2 + y2 = a2cos6θsin4θ + a2sin6θcos4θ
= a2sin4θ cos4θ (1)
= a2 sin4θ cos4θ
also xy = a2 sin5θ cos5θ
∴ [(x2 + y2)m/(xy)n]
= [(a2m sin4mθ cos4mθ)/(a2n sin5nθ cos5nθ)]
= a(2m – n) ∙ sin(4m – 5n)θ ∙ cos(4m – 5n)θ
∵ expression is free from θ
⇒ sin(4m – 5n)θ ∙ cos(4m – 5n)θ = 1
⇒ 4m – 5n = 0
∴ 4m = 5n.