Question

If ABCD is a parallelogram and E is the mid point of AB, show by vector method that DE trisects and is trisected by AC.

Answer 1

Also let K be a point on AC, such that AK : AC = 1 : 3

From (i) and (ii) we find that :

and so we conclude that K and M coincide. i.e. DE trisect AC and is trisected by AC.