y = A.sin2π(t/T-x/λ) ....... (i)
yₘₐₓ = A. {Because maximum value of sine = 1}
v = ∂y/∂t = A.cos 2π(t/T-x/λ)*2π/T
→vₘₐₓ = 2πA/T. {} Because also maximum value of cosine =1}
a = ∂²y/∂t² = A.sin2π(t/T-x/λ)*4π²/T²
→aₘₐₓ = 4π²A/T²
Now yₘₐₓ/vₘₐₓ =A/(2πA/T) = T/2π and vₘₐₓ/aₘₐₓ = (2πA/T)/(4π²A/T²) =T/2π
Hence, yₘₐₓ/vₘₐₓ = vₘₐₓ/aₘₐₓ.
We cannot use Componendo and Dividendo because addition and subtraction are allowed only between quantities having same unit or dimension. Here yₘₐₓ, vₘₐₓ and aₘₐₓ all have different units and dimensions.