Question

An automobile engine develops 100 kw when rotating at a speed of 1800 r.p.m. what torque does it deliver ?

(A) 350 Nm

(B) 440 Nm

(C) 531 Nm

(D) 628 Nm

Answer 1

Correct option: (C) 531 Nm

Explanation:

p = power = 100 kω

ω = speed = 1800 rpm = [(2π × 1800) / 60] = 60π rad/sec

P = τ ∙ ω

τ = (p/ω)

= [(100 × 103) / (60π)]

= 530.78 ≈ 531 Nm