If the lengths of perpendicular drawn from the origin to the lines xcos α – ysin α = sin2aα and xsinα + ycosα = cos2α are p and q respectively, then p2 + q2 = …….
(a) 4
(b) 3
(c) 2
(d) 1
The correct option (d) 1
Explanation:
from given condition,
p = [{|(0)cosα – (0)sinα – sin2aα|}/√(cos2α + sin2α)]
∴ p = sin2α and similarly
q = cos2α
∴ p2 + q2 = sin22α + cos22α
∴ p2 + q2 = 1
