+3 votes
in JEE by kratos

Match the shape of graph with given pair of physical quantities.

Physical Quantities

(x) Moment of inertia ➙ distance

(y) loge Er ➙ loge L

(z) Angular momentum(L) ➙ angular velocity (ω)

(w) loge L ➙ loge P

Shape of graph

1 Answer

+4 votes
by kratos
 
Best answer

Correct option: (B)

Explanation:

(x) MI ∝ (distance)2 since I = Icm + md2. at d = 0, I ≠ 0

(y) Er = [L2 / (∝I)]

loge Er = 2loge Lr – 2loge ∝I

graph is straight line (between loge Er& loge L) and nonzero at loge L = 0 (value is negative)

(z) L = Iω

L ∝ ω

straight line

(ω) L = r × p

loge L = loger + logeP

at logeP = 0, logeL ≠ 0 hence not passing through origin.

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