Correct option: (B)
Explanation:
(x) MI ∝ (distance)2 since I = Icm + md2. at d = 0, I ≠ 0
(y) Er = [L2 / (∝I)]
loge Er = 2loge Lr – 2loge ∝I
graph is straight line (between loge Er& loge L) and nonzero at loge L = 0 (value is negative)
(z) L = Iω
L ∝ ω
straight line
(ω) L = r × p
loge L = loger + logeP
at logeP = 0, logeL ≠ 0 hence not passing through origin.