If the length of perpendicular drawn from origin to a line is 10 and α = – (5π/6) then the equation of line would be …..
(a) √3x + y = 20
(b) √3x – y = 20
(c) √3x + y + 20 = 0
(d) √3x – y + 20 = 0
The correct option (c) √3x + y + 20 = 0
Explanation:
From equation, xcosα + ysinα = p
we get,
xcos[– (5π/6)] + ysin[– (5π/6)] = p
∴ – xcos(π/6) – ysin(π/6) = 10
∴ – x(√3/2) – (y/2) = 10
∴ √3x + y + 20 = 0
