+3 votes
in JEE by kratos

The area of the triangle formed by the point (a, a2), (b, b2), (c, c2) is (a, b, c are three consecutive odd integers)

(a) (1/2) (a – b) (b – c) sq unit

(b) 8 sq unit

(c) 16 sq unit

(d) (1/2) (a – b) (b – c) (a + b + c) sq unit

1 Answer

+5 votes
by kratos
 
Best answer

The correct option (b) 8 sq unit

Explanation:

A = (1/2)[(bc2 – b2c) – a(c2 – b2) + a2(c – b)]

A = (1/2)(b – c)(a – b)(c – a)

∵ a, b, c are consecutive add integer

∴ A = (1/2)(– 2)(– 2)(4) = 8 sq. unit

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