Question

If the height of a satellite from the earth is negligible in comparison of the radius of the earth R, the orbital velocity of the satellite is

(A) gR

(B) (gR / 2)

(C) √(g/R)

(D) √(gR)

Answer 1

Correct option: (D) √(gR)

Explanation:

Orbital velocity near to earth = [(escape velocity) / √2]

V = (Ve / √2)

V = [{√(2gr)} / √2] = √(gR)