On increasing the length by 0.5 mm in a steel wire of length 2 m and area of cross-section 2 mm2 the force required is..... [Y for steel = 2.2 × 1011 N/m ]
(A) 1.1 × 105 N
(B) 1.1 × 104 N
(C) 1.1 × 103 N
(D) 1.1 × 102 N
Correct option: (D) 1.1 × 102 N
Explanation:
F = [(YAℓ) / L]
From given data,
F = {(2.2 × 1011 × 2 × 10–6 × 0.5 × 10–3) / 2}
= 1.1 × 102 N
