The Boolean expression ((p ∧ q) ∨ (p ∨ ~q)) ∨ (~ p ∧ ~q) is equivalent to :
(1) p ∧ q
(2) (~ p) ∧ (~ q)
(3) p ∧ (~ q)
(4) p ∨ (~ q)
The correct option (2) (~ p) ∧ (~ q)
Explanation:
(ii) (~ p) ∧ (~ q)